In a right-angled triangle ABC, angle B is 90 degrees, angle A is 30 degrees, hypotenuse AC = 19 cm. Find BC and angle C.

In a right-angled triangle, the sum of its acute angles is 900, then the angle ACB = (90 – BAC) = (90 – 30) = 60.

The BC leg is located opposite an angle of 300, then its length is equal to half the length of the AC hypotenuse.

BC = AC / 2 = 19/2 = 9.5 cm.

Answer: Angle C is 60, leg BC is 9.5 cm.



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