In a right-angled triangle ABC (angle C = 90 *) AC = 10 cm, angle B = 60 *. Find the distance from the vertex C

In a right-angled triangle ABC (angle C = 90 *) AC = 10 cm, angle B = 60 *. Find the distance from the vertex C to the hypotenuse AB

The distance from vertex C to hypotenuse AB is the length of the perpendicular drawn from point C to side AB. Let’s designate this perpendicular CD.
In triangle ABC, angle A = 90 ° – 60 ° = 30 °.
Consider triangle ADC, it is known in it:
Hypotenuse AC = 10 cm, angle A = 30 °.
The CD leg lies opposite an angle of 30 °, which means it is equal to half the hypotenuse.
CD = 1 / 2AC = 5 cm.
Answer: 5 cm.