In a right-angled triangle ABC, angle C = 90 degrees, AB = 10cm, BC = 5cm Find the angles by which

In a right-angled triangle ABC, angle C = 90 degrees, AB = 10cm, BC = 5cm Find the angles by which the height CH divides angle C

1. In a right-angled triangle ABC, the length of the BC leg is 1/2 the length of the hypotenuse AB (10: 5 = 2). Therefore, this leg is opposite an angle of 30 °. That is, the angle at the vertex A of the triangle is 30 °.

2. We calculate the value of the angle АСН, taking into account that the sum of the angles of the triangle is equal to 180 °, and the angle АНC = 90 °:

Angle АСН = 180 ° – 30 ° – 90 ° = 60 °.

3. We calculate the value of the BCH angle: 90 ° – 60 ° = 30 °.

Answer: BCН angle = 30 °, ACН angle = 60 °