In a right-angled triangle ABC, angle C = 90, find the value of the sine of angle A. if the cosine of angle B = 3 \ 5.

The cosine of angle B is the ratio of the adjacent leg to the hypotenuse. From the given data it is known that the cosine of the angle B is 3/5. This means that the side BC is 3 cm, and the side AB is 5 cm.The sine of angle A is equal to the ratio of the opposite leg to the hypotenuse, therefore the sine of the angle A = BC / AB, hence we conclude that the sine of angle A is 3/5, or in decimal fraction 0.6.
Answer: Sine of angle A = 3/5 or 0.6.



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