In a right-angled triangle ABC C = 90 °, A = 30 °, AC = 6cm. Find the height of the CD, drawn from the top of the right angle.

The height CD divides the right-angled triangle ABC into 2 right-angled triangles – ADC and BDC. In triangle ADC, side AC is the hypotenuse, angle A is 30 °, and CD is the leg opposite to angle A.

Find CD through the sine of angle A.

СD = 6 cm * sin30 ° = 6 cm * 0.5 = 3 cm.

Answer: CD height is 3 cm.



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