In a right-angled triangle ABC from the vertex C of the right angle, the height CD is drawn
In a right-angled triangle ABC from the vertex C of the right angle, the height CD is drawn, and in triangle ADC its bisector CE is drawn. Find the length of the segment BE, if it is known that AC = 6, BC = 8.
By the Pythagorean theorem, we determine the length of the hypotenuse AB.
AB ^ 2 = AC ^ 2 + BC ^ 2 = 36 + 64 = 100. AB = 10 cm.
Let the length of the segment AD = X cm, then ВD = (10 – X) cm.
Let us express the height of the СD in right-angled triangles ВСD and AСD.
СD ^ 2 = AC ^ 2 – AD ^ 2 = 36 – X2.
СD ^ 2 = BC ^ 2 – BD ^ 2 = 64 – (10 – X) 2.
Then: 36 – X2 = 64 – 100 + 20 * X – X2.
20 * X = 72.
X = AD = 72/20 = 3.6 cm.
Then BD = 10 – 3.6 = 6.4 cm.
Let’s determine the height of the CD. CD^2 = 36 – 3.62 = 23.04.
CD = 4.8 cm.
Let the length of the segment BE = X cm, then DE = (6.4 – X) cm.
In the BCD triangle, we use the property of the angle bisector.
BC / BE = CD / DE.
8 / X = 4.8 / (6.4 – X).
4.8 * X = 51.2 – 8 * X.
12.8 * X = 51.2.
X = BE = 51.2 / 12.8 = 4 cm.
Answer: The length of the segment BE is 4 cm.