In a right-angled triangle ABC leg AC = 55 and the height CH lowered to the hypotenuse is 44.

In a right-angled triangle ABC leg AC = 55 and the height CH lowered to the hypotenuse is 44. Find the sin of the angle ABC.

Triangles АСН and ВСН are similar in acute angle, angle СНН = АСН.

CosACH = CH / AC = 44/55 = 4/5.

Then Sin2ACH = 1 – Cos2ACH = 1 – 16/25 = 9/25

SinACH = SinCBH = SinABC = 3/5.

Answer: The sine of the angle ABC is 3/5.



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