In a right-angled triangle ABC, legs AB AC are 3 and 4 cm, respectively, find the sine B cos B tg B.

Let us determine the length of the hypotenuse of the BC by the Pythagorean theorem.

BC ^ 2 = AC ^ 2 + AB ^ 2 = 16 + 9 = 25.

BC = 5 cm.

Determine the sine of the angle ABC: SinABC = AC / BC = 4/5 = 0.8.

Let’s calculate the cosine of the angle ABC: CosABC = AB / BC = 3/5 = 0.6.

Then the tangent of the angle ABC is equal to:

tgABC = SinABC / CosABC = 0.8 / 0.6 = 4/3 = 1 (1/3).

Answer: SinBC = 0.8, CosABC = 0.6, tgABC = 1 (1/3).



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