In a right-angled triangle ABC, legs AC = 3cm BC = 4cm, and the hypotenuse 5cm, find the sine of angle A.
| June 12, 2021 | education
The sine of an acute angle of a right-angled triangle is the ratio of the leg opposite to a given angle to the hypotenuse.
In triangle ABC there is hypotenuse AB, so the right angle is angle C. Angle B lies opposite the leg AC. Opposite corner A lies leg BC.
sin A = BC / AB;
sin A = 4/5 = 0.8.
Answer. 0.8.
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