In a right-angled triangle ABC, the angle, B = 90, BC = 5, AB = 12, AD is the bisector. Find: SΔABC.

We need to find the area of a right-angled triangle. To do this, we need to use the formula for calculating the area:

S = (a * b) * 1/2

Where a and b are the legs of a right-angled triangle.

From the problem statement, we know that:

a = AB = 12
b = BC = 5

Then we get the area of a right-angled triangle:

S = (a * b) * 1/2 = (12 * 5) * 1/2 = 5 * 12/2 = 5 * 6 = 30