In a right-angled triangle ABC, the angle C is straight. find the perimeter of the triangle if (angle) A = 30 ° AC = √48 B = 4.

The BC leg in a right-angled triangle ABC is located opposite the angle 30, then its length is equal to half the length of the hypotenuse AB. BC = AB / 2.

AB = 2 * BC = 2 * 8 = 8 cm.

Then the perimeter of the triangle ABC will be equal to: Ravs = AC + BC + AB = √48 + 4 + 8 = 4 * √3 + 12 = 4 * (3 + √3) cm.

Answer: The perimeter of the triangle is 4 * (3 + √3) cm.



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