In a right-angled triangle ABC, the hypotenuse AB = 16 cm and the angle of you = 15 degrees. The area is …?

It is known that the area of a right-angled triangle is half the product of the legs:
S = 1/2 AC * BC.
In this case, the legs of a right-angled triangle ABC can be defined as the product of the hypotenuse and sin BAC or cos BAC, respectively.
Thus, the leg BC opposite to the angle BAC = AB sin BAC = 16 * sin 15 = 4.14 cm, and the adjacent leg AC = AB cos BAC = 16 * cos 15 = 15.45 cm.
As a result, the area of a given right-angled triangle ABC is equal to:
S = 1/2 * 4.14 * 15.45 = 31.98 cm ^ 2.