In a right-angled triangle ABC, the leg AC = 20, and the height CH, the lowered hypotenuse, is 3√39.

In a right-angled triangle ABC, the leg AC = 20, and the height CH, the lowered hypotenuse, is 3√39. Find the cos of the angle CAB.

In a right-angled triangle ACH SinCAH = CH / AC = 3 * √39 / 20.

Then Cos2CAH = 1 – Sin2CAH = 1 – 351/400 = (400 – 351) / 400 = 49/400.

CosCAH = CosCAB = 7/20.

Answer: The cosine of the angle CAB is 7/20.



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