In a right-angled triangle ABC with a right angle C and an angle A equal to 48 degrees

In a right-angled triangle ABC with a right angle C and an angle A equal to 48 degrees, the height CD is drawn. Find the corner BCD.

The height CD, drawn in the right-angled triangle ABC, divides the triangle ABC into two right-angled triangles ACD, BCD, with a right angle D in each of them.

To find the angle BCD, you need to find the angle B in triangle ABC.

The sum of the angles in a triangle is 180 °, angle C = 90 ° (straight line), angle A is 48 °:

A + B + C = 180 °;

B = 180 ° – 90 ° – 48 °;

B = 90 ° – 48 °;

B = 42 °.

We find the angle ВСD by applying the same rule for the triangle BCD, where
D = 90 °, B = 42 °.

BCD = 180 ° – 90 ° – 42 °.

BCD = 90 ° – 42 °;

BCD = 48 °.