In a right-angled triangle ABC with a right angle C cos A = 1/2 leg AC = 6 find the hypotenuse AB.
September 23, 2021 | education
| Since CosA = 1/2, the angle BAC = arcos (1/2) = 60.
Then the angle ABC = (90 – 60) = 30.
The AC leg lies opposite an angle of 30, then its length is equal to half the length of the AC hypotenuse.
AC = AB / 2.
AB = 2 * AC = 2 * 6 = 12 cm.
Second way.
The cosine of an acute angle of a right-angled triangle is the ratio of the length of the adjacent leg to the length of the hypotenuse.
CosA = AC / AB.
AB = AC / CosA = 6 / (1/2) = 12 cm.
Answer: The length of the hypotenuse AB is 12 cm.
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