In a right-angled triangle ABC with a right angle C cos A = 1/2 leg AC = 6 find the hypotenuse AB.

Since CosA = 1/2, the angle BAC = arcos (1/2) = 60.

Then the angle ABC = (90 – 60) = 30.

The AC leg lies opposite an angle of 30, then its length is equal to half the length of the AC hypotenuse.

AC = AB / 2.

AB = 2 * AC = 2 * 6 = 12 cm.

Second way.

The cosine of an acute angle of a right-angled triangle is the ratio of the length of the adjacent leg to the length of the hypotenuse.

CosA = AC / AB.

AB = AC / CosA = 6 / (1/2) = 12 cm.

Answer: The length of the hypotenuse AB is 12 cm.



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