In a right-angled triangle ABC with a right angle C sinA * cosB = 0.36. Find tgA.
| March 26, 2021 | education
In a right-angled triangle, the sine of one acute angle of a right-angled triangle is equal to the cosine of another acute angle.
CosB = SinA.
Since, by condition, SinA * CosB = 0.36, then Sin2A = Cos2B = 0.36.
SinA = CosB = 0.6.
From the basic trigonometric identity: Cos2A = 1 – Sin2A = 1 – 0.36 = 0.64.
CosA = 0.8.
Then tgA = SinA / CosA = 0.6 / 0.8 = 3/4.
Answer: The tangent of angle A is 3/4.
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