In a right-angled triangle ABC with right angle C, the outside angle at apex A is 120 degrees

In a right-angled triangle ABC with right angle C, the outside angle at apex A is 120 degrees, AC + AB = 18cm. Find AC and AB.

The angle DAС and BAC are adjacent angles, the sum of which is 180.

The angle DAС + BAC = 180, then the angle BAC = 180 – DAС = 180 – 120 = 60.

Consider a right-angled triangle ABC, in which the angle BAC = 60, then the angle ABC = 180 – BAC – ACB = 180 – 60 – 90 = 30.

Then the leg AC lies against an angle of 30 and, accordingly, is equal to half the length of the hypotenuse AB.

AC = AB / 2.

By condition, AC + AB = 18 cm.

Then AC = 18 – AB.

AB / 2 = 18 – AB.

AB = 36 – 2 * AB.

3 * AB = 36.

AB = 36/3 = 12 cm.

AC = 18 – AB = 18 – 12 = 6 cm.

Answer: AC = 12 cm, AB = 6 cm.



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