In a right-angled triangle, angle C is 90 degrees AC = 28 centimeters AB = 35 centimeters find the sine of B.

Since the sine of an angle is by definition the ratio of the opposite

leg to the hypotenuse, then the sine of angle B in a right-angled triangle ACB will be equal to the following:

sin B = AC / AB, where AC = 28 cm (this is the leg), AB = 35 cm (this is the hypotenuse).

Sin B = 28/35 = 0.80.

Answer: Sin B = 0.80.



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