In a right-angled triangle CDE with a right angle C, the bisector EF is drawn, with FC = 13 cm.
| September 7, 2021 | education
In a right-angled triangle CDE with a right angle C, the bisector EF is drawn, with FC = 13 cm.Find the distance from point F to line DE
1. To find the distance from point F to line DE, it is necessary to lower the perpendicular FO from point F to the side DE.
2. We got two triangles FOE and FCE, in which, according to the problem statement, angle OEF = angle CEF, angle FOE and angle FCE are straight lines, so angle OFE = angle EFC, side CE in triangles is common, so triangle OFC = triangle FCE according to the third attribute equality of triangles.
And so the sides OF and FC are equal.
By the condition of the problem FC = 13 cm, hence FO = 13 cm.
Answer: The distance from point F to line DE is 13 centimeters.
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