In a right-angled triangle MEF (angle E = 90 degrees) C belongs to ME, D belongs to MF
| April 27, 2021 | education
In a right-angled triangle MEF (angle E = 90 degrees) C belongs to ME, D belongs to MF, and CD belongs to EF, K belongs to MD, angle KCD = 40 degrees. What is the MCK angle?
The ME segment is perpendicular to EF, since the MEF triangle is rectangular.
Since the segment CD is parallel to EF by condition, then CD is perpendicular to the segment ME, then the angle of the MCD is straight.
Then the angle MSC = MCD – KCD = 90 – 40 = 50.
Answer: The angle of the MCS is 50.
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