In a right-angled triangle MNK, the angle is K = 90 degrees, KM = 6cm, NK = 6√3cm

In a right-angled triangle MNK, the angle is K = 90 degrees, KM = 6cm, NK = 6√3cm, KD is the median. Find the corner KDN.

In a right-angled triangle MHK, according to the Pythagorean theorem, we determine the length of the hypotenuse MH.

MH ^ 2 = HK ^ 2 + KM ^ 2 = 108 + 36 = 144.

MH = 12 cm.

KD is the median drawn to the hypotenuse from the vertex of the straight edge, then e length is equal to half the length of the hypotenuse.

КD = НD = МD = МH / 2 = 12/2 = 6 cm.

In the triangle KMD, KM = KD = MD = 6 cm, then the triangle KMD is equilateral, then the angle KDM = 60.

The KDH angle is adjacent to the KDM angle, the sum of which is 180, then the KDH angle = 180 – 60 = 120.

Answer: The value of the KDH angle is 120.



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