In a right-angled triangle MNP, angle N = 90 degrees., NP = 5 cm, MN = 8 cm. Through point P

In a right-angled triangle MNP, angle N = 90 degrees., NP = 5 cm, MN = 8 cm. Through point P, a straight line PК is drawn parallel to the straight line MN. Then the distance between straight lines MN and PК will be equal?

Since, according to the condition, the side of the MN is parallel to the straight line PK, the shortest distance between these straight lines is the segment AB perpendicular to both segments.

In the quadrangle ABPN, all angles are straight, then it is a rectangle, which means AB = NP = 5 cm.

Answer: The distance between straight lines MN and PK is 5 cm.



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