In a right-angled triangle, one of the legs is 5 √3 cm. Find the second leg if the angle adjacent to this leg is 30 degrees.

Let us determine the length of the BC leg through the tangent of the acute angle.

tgBAC = BC / AB.

BC = AB * tg30 = 5 * √3 * (1 / √3) = 5 cm.



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