In a right-angled triangle, the difference between the largest and smallest outer angles is 70 degrees

In a right-angled triangle, the difference between the largest and smallest outer angles is 70 degrees. Find the sharp corners of this triangle.

The largest outer corner of a triangle is adjacent to the smallest inner corner, and the smallest outer is adjacent to the largest inner corner.

The largest inner corner of a right-angled triangle is a right angle, whose outer angle is also 90. Angle CBM = (180 – 90) = 90.

Then, by condition, the external angle BАК = CBM + 70 = 90 + 70 = 160.

The internal angle BAC adjacent to the angle BAC is equal to: BAC = (180 – 160) = 20.

Angle ACB = (180 – ABC – BAC) = (180 – 90 – 20) = 70.

Answer: The acute angles of the triangle are 20, 70.