In a right-angled triangle, the hypotenuse is 6 cm, and one of the legs is 4 cm. Find the length of the second leg.

Let ABC be a given triangle (angle C = 90 °). AB = 6 cm, AC = 4 cm. Find BC.

By the Pythagorean theorem: the square of the hypotenuse is equal to the sum of the squares of the legs.

AB² = AC² + BC².

6² = 4² + ВС².

36 = 16 + BC².

ВС² = 36 – 16 = 20.

BC = √20 = √ (4 * 5) = 2√5.

Answer: the second leg is 2√5.



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