In a right-angled triangle, the leg is 15 cm and its projection onto the hypotenuse is 9 cm.

The task is simple, it can be solved in just a couple of steps. To find out the answer, you must first create a geometric problem. We compose:

Given:

ΔABС,

B = 90 °,

AB = 15,

ВD height at the base,

BP = 9.

Decision:

AC = AB² / AD = 225/9 = 25;

ВС² = DС * АС = 16 * 25;

BC = 20;

cosA = 15/25 = 3/5;

sinA = 20/25 = 4/5.



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