In a right-angled triangle, the legs are 8 and 15 cm. Find: sin, cos and tg of the smaller acute angle.

Let a = 8 cm, b = 15 cm, we find c = √ (8 ^ 2 + 15 ^ 2) = √ (64 + 225) = √289 = 17 cm.

sin A = a / c = 8/17; cos A = in / c = 15/17; tg A = a / b = 8/15; in this case, we take into account that the smaller angle <A against the smaller side a = 8 cm.



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