In a room with a volume of 140 m ^ 3 there is air containing saturated vapors of mercury with a temperature of 27 C.

In a room with a volume of 140 m ^ 3 there is air containing saturated vapors of mercury with a temperature of 27 C. Determine the mass of mercury in the room if the pressure of saturated vapors of mercury is 0.43 Pa.

To calculate the value of the mass of mercury in a given room, we transform the Mendeleev-Clapeyron equation: m = P * V * MHg / (R * T).

Constants and variables: P – pressure of mercury vapor (P = 0.43 Pa); V is the volume of the room (V = 140 m3); MHg – molar mass (MHg = 200.592 g / mol); R – universal gas constant (R = 8.31 J / (K * mol)); T is the temperature of mercury (T = 300 K).

Let’s calculate: m = P * V * MHg / (R * T) = 0.43 * 140 * 200.592 / (8.31 * 300) ≈ 4.84 g.

Answer: This room contains 4.84 g of mercury.