In a room with dimensions of 10 × 6 m2, granite tiles are laid. The dimensions of one tile are 50 × 25 cm2, and its weight is 4 kg.

| November 18, 2020 | education

In a room with dimensions of 10 × 6 m2, granite tiles are laid. The dimensions of one tile are 50 × 25 cm2, and its weight is 4 kg. How many kilograms of tiles are needed to completely cover the floor? Round off the answer to whole integers.

S = 10 * 6 m ^ 2 = 60 m ^ 2.
S1 = 50 * 25 cm ^ 2 = 0.125 m ^ 2.
m1 = 4 kg.
m -?
The room has the shape of a rectangle with dimensions of 10 m by 6 m, so its area S = 10 m * 6 m = 60 m ^ 2.
The tile also has a rectangular shape with dimensions of 50 cm by 25 cm or 0.5 m by 0.25 m.
The area of one tile will be S1 = 50 * 25 cm ^ 2 = 0.5 m * 0.25 m = 0.125 m ^ 2.
Find the number of tiles N, which are needed to cover the surface of the room.
N = S / S1.
m = N * m1.
m = S * m1 / S1.
m = 60 m ^ 2 * 4 kg / 0.125 m ^ 2 = 1920 kg.
Answer: you need m = 1920 kg of tiles.



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