In a saucepan, 2 kg of water was heated at 20C. How much energy is consumed for heating? Specific heat capacity of water 4200 J / kg
m = 2 kilograms is the mass of water in the pan;
dT = 20 degrees Celsius – the temperature at which the water was heated;
c = 4200 J / (kg * C) – specific heat of water.
It is required to determine Q (Joule) – the amount of consumed energy.
Since the problem statement is not specified, the energy losses associated with heating the pan itself are not taken into account. Then:
Q = c * m * dT = 2 * 4200 * 20 = 40 * 4200 = 168000 Joules = 168 kJ.
Answer: to heat the water, an energy equal to 168 kJ (168,000 Joules) was consumed.
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