In a shaft 0.6 km deep, the mask pressure is 760 m, which is equal to the pressure on the ground.

Given:

H = 0.6 kilometers = 600 meters – the depth of the mine;

P1 = 760 millimeters of mercury = 101325 Pascals – pressure at the bottom of the mine;

с = 12/133 m / Pa – coefficient of atmospheric pressure change depending on depth.

It is required to determine the pressure at ground level P (Pascal).

P = P1 – P1 / c = 101325 – 101325 * 12/133 = 101325 – 761.8 * 12 = 101325 – 9142 = 92183 Pascals, or 691 millimeters of mercury.

Answer: The pressure on the surface of the earth is 92,183 Pascal (691 millimeters of mercury).