In a smelting furnace, 0.1 kg of coal was burned and 2 kg of copper taken at 23 degrees

In a smelting furnace, 0.1 kg of coal was burned and 2 kg of copper taken at 23 degrees Celsius was melted. Determine the efficiency of the furnace.

Furnace efficiency:

η = (Ap. / Az.) * 100%.

Useful work, Ap. = Q = Q1 + Q2, where Q1 = С * m1 * (tк – tн), Q2 = λ * m1.

С = 400 J / (К * kg), m1 = 2 kg, tк = 1083 ºС, tн = 23 ºС, λ = 2.1 * 105 J / kg.

Work expended, Az. = q * m1.

q = 27 MJ = 27 * 106 J / kg, m1 = 0.1 kg.

η = (Ap. / Az.) * 100% = ((С * m1 * (tк – tн) + λ * m1) / (q * m1)) * 100% = ((400 * 2 * (1083 – 23 ) + 2.1 * 105 * 2) / (27 * 106 * 0.1)) * 100% = ((848000 + 4200000) / 2700000) * 100% = 0.47 * 100% = 47%.



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