In a solution containing 12 g of copper sulfate was dipped 8 g of iron filings. Calculate the mass of the salt formed.
| December 8, 2020 | education
CuSO4 + Fe = FeSO4 + Cu
n (CuSO4) = m / M = 12 g / 160 g / mol = 0.075 mol (deficiency)
n (Fe) = m / M = 8 g / 56 g / mol = 0.143 mol (excess)
the calculation is carried out by a disadvantage.
According to the reaction equation n (FeSO4) = n (CuSO4)
n (FeSO4) = 0.075 mol
m (FeSO4) = n x M = 0.075 mol x 152 g / mol = 11.4 g
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