In a solution weighing 200 g with a mass fraction of calcium chloride of 12% was added and 20 g of calcium chloride (Cl2Ca)

In a solution weighing 200 g with a mass fraction of calcium chloride of 12% was added and 20 g of calcium chloride (Cl2Ca) was dissolved and determine the mass fraction of calcium chloride in this solution.

The mass fraction in this case is the ratio of the mass of the solute to the mass of the solution. After adding a certain amount of soluble salt to the solution, both the mass of the solution and the mass fraction will increase.

The algorithm for determining the mass fraction is as follows:

1. find the mass of salt in the original solution;

2. calculate the mass of the salt and the mass of the new solution after adding calcium chloride;

3. calculate the resulting mass fraction of CaCl2 in the solution.

The solution of the problem:

1.m ‘(CaCl2) = m1 (solution) * ω / 100 = 200 * 12/100 = 24 g of calcium chloride in the original solution.

2. m “(CaCl2) = 24 + 20 = 44 g of calcium chloride in a new solution.

m2 (solution) = 200 + 20 = 220 g – the mass of the resulting solution.

3. ω ‘(CaCl2) = 100 * m “(CaCl2) / m2 (solution) = 100 * 44/220 = 20% concentration of the new solution.

Answer: Mass fraction of calcium chloride is 20%.