In a square, the radius of the circumscribed circle is 2√10 cm Find the perimeter of the square

The radius of the circumscribed circle is half the length of the diagonal of the square.

R = (√AB ^ 2 + AD ^ 2) / 2.

4 * R ^ 2 = 2 * AB ^ 2.

AB = R * √2 = 2 * √10 * √2 = 2 * √20 = 4 * √5 cm.

Then Ravsd = 4 * AB = 16 * √5 cm.

Answer: The perimeter of the square is 16 * √5 cm.



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