In a steel cylinder with a capacity of 40 liters at a temperature of 23C under a pressure of 2.0 MPa

In a steel cylinder with a capacity of 40 liters at a temperature of 23C under a pressure of 2.0 MPa there is oxygen. Determine the mass of oxygen in the cylinder.

Initial data: V (balloon volume) = 40 l = 0.04 m ^ 3; Т (absolute temperature of oxygen) = 300 К (27 ºС); P (oxygen pressure in the cylinder) = 2 MPa = 2 * 10 ^ 6 Pa.

Reference data: R (universal gas constant) = 8.31 J / (mol * K)); M (molar mass) = 0.032 kg / mol.

The mass of oxygen in the cylinder is determined from the Mendeleev – Clapeyron equation:

P * V = (m / M) * R * T.

m = P * V * M / (R * T).

Let’s do the calculation:

m = 2 * 10 ^ 6 * 0.04 * 0.032 / (8.31 * 300) ≈ 1 kg.

Answer: The mass of oxygen is 1 kg.