In a tank filled with oil, at a depth of 3 m, there is a valve with an opening area of 30 cm ^ 2.

In a tank filled with oil, at a depth of 3 m, there is a valve with an opening area of 30 cm ^ 2. With what force does the oil press on the tap?

These tasks: h (distance from the oil surface to the crane) = 3 m; S (area of the tap hole in the tank) = 30 cm2 (in SI S = 30 * 10-4 m2).

Reference values: g (acceleration due to gravity) ≈ 10 m / s2; ρн (oil density) = 800 kg / m3.

The force of oil pressure on the valve installed in the tank can be determined by the formula: F = P * S = ρн * g * h * S.

Let’s calculate: F = 800 * 10 * 3 * 30 * 10-4 = 72 N.

Answer: Oil presses on the tap with a force of 72 N.