In a trapezoid ABCD, AD = 4, BC = 1 and its area is 35 Nights, area ABC?
August 30, 2021 | education|
Let’s build the height of the HВ trapezoid ABCD.
The area of the trapezoid is equal to the product of the half-sum of the lengths of its bases and the height.
Savsd = (ВС + АD) * ВН / 2.
Then ВН = 2 * Savsd / (BC + AD) = 2 * 35 / (1 + 4) = 70/5 = 15 cm.
In triangle ABC, we will build the height of AK to the base of the BC.
AK = ВН = 15 cm, since AKВН is a rectangle.
Determine the area of the triangle ABC.
Savs = BC * AK / 2 = 1 * 15/2 = 7.5 cm2.
Answer: The area of triangle ABC is 7.5 cm2.
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