In a trapezoid with an area of 132, the height is 6, and the Difference of parallel sides is 12
| September 8, 2021 | education
In a trapezoid with an area of 132, the height is 6, and the Difference of parallel sides is 12, find the length of the larger base.
Apply the formula for the area of a trapezoid and substitute the relevant values.
Savsd = (BC + AD) * CH / 2.
132 = (BC + AD) * 6/2.
(ВС + АD) = 132/3 = 44 cm. (1).
By condition, (АD – ВС) = 12 see (2).
Let’s solve a system of two equations with two unknowns.
Add equation 1 to equation 2.
BC + AD + AD – BC = 44 + 12.
2 * AD = 56.
AD = 56/2 = 28 cm.
Answer: The length of the larger base is 28 cm.
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