In a triangle ОВМ, the angle BОС = 90 degrees, ОН is perpendicular to BM, ВМ = 26dm, ВН = 18dm. Find OH and OB.

Let us determine the length of the segment MH.

МН = ВМ – ВН = 26 – 18 = 8 dm.

Since OH is perpendicular to ВM, then OH is the height drawn from a right angle to the hypotenuse, then OH ^ 2 = BH * MH = 18 * 8 = 144.

OH = 12 cm.

In the right-angled triangle ВOН, according to the Pythagorean theorem, we determine the length of the hypotenuse OB.

ОВ ^ 2 = ВН ^ 2 + ОН ^ 2 = 324 + 144 = 468.

ОВ = 6 * √13 cm.

Answer: Length OH = 12 cm, length OB = 6 * √13 cm.



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