In a triangle ABC AB = 2 cm AC = 8 cm cosA = 1/8. Find BC

Let us apply the cosine theorem for a triangle to solve.

BC ^ 2 = AC ^ 2 + AB ^ 2 – 2 * AC * AB * CosA = 64 + 4 – 2 * 8 * 2 * (1/8) = 68 – 4 = 64

BC = √64 = 8 cm.

Answer: The BC side of the triangle is 8 cm.



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