In a triangle ABC AB = 2cm, AC = 2cm, cosA = 1/8. Find BC.

AB lies opposite angle C, AC – opposite angle B, BC – opposite angle A.

Angle A is formed by sides AB and AC.

In accordance with the cosine theorem, we write:

BC ^ 2 = AB ^ 2 + AC ^ 2 – 2cosA * AB * AC = 2 ^ 2 + 2 ^ 2 – 2 * 1/8 * 2 * 2 = 8 – 1 = 7 cm ^ 2.

BC = √ (7 cm ^ 2) = √7 cm

Answer: √ 7 cm.



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