Based on the conditions of this problem, it can be judged that the ABC triangle is rectangular, since the sum of the squares of the legs is equal to the sum of the square of the hypotenuse.
BC2 = AB2 + AC2
5 * 5 = 3 * 3 + 4 * 4.
25 = 9 + 16.
25 = 25.
In this case, the largest angle will be the total angle for the two legs, which is right and is 90 °.
The largest angle is CAB, its value is 90 °.
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