# In a triangle ABC AB = 5, BC = 3 AC = 7. Point M is located on BC so that the distances from point

October 4, 2021 | education

| **In a triangle ABC AB = 5, BC = 3 AC = 7. Point M is located on BC so that the distances from point to straight lines AB and AC are equal. Find MC.**

We know that point M is equidistant from AB and AC, which means it lies on the bisector AM of the angle BAC.

We will assume that MC = x, then AB / BM = AC / MC.

We got the proportion, we need to substitute the data and calculate:

5 / (3 – X) = 7 / X;

X = 1.75.

Since x = MC, we found MC = 1.75.

Answer: MS = 1.75.

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