In a triangle ABC AB = 7√3, BC = 14cm, angle B = 150 ° Find the area of the triangle?

Two sides of the triangle are known: AB = 7 √3 cm; ВС = 14 cm and the angle between them <В = 150 °;

sin 150 ° = 0.5; Find the area of a triangle.

The formula for calculating the area on two sides and the sine of the angle between them:

S = 1/2 AB * BC * sin <B = 1/2 * 7√3 * 14 * 0.5 = 24.5 √3 (cm²).



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