In a triangle ABC AB = BC, CH-height, AB = 10, BH = 6. Find the sine of the angle ABC.
| November 23, 2020 | education
Since CH is the height at AB.
By the Pythagorean theorem, we find CH.
CH = √BC ^ 2-BH ^ 2 =√100-36 =√64 = 8
From here we find the sine ABC = CH / BC = 8/10 = 0.8
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