In a triangle ABC AC = BC = 30, sin B = √3 / 2. Find AB.

Since, by the condition SinABC = √3 / 2, then the angle ABC = arcsin (√3 / 2) = 60.

By condition, AC = BC = 30 cm, then the ABC triangle is isosceles, and since the ABC angle = 60, the ABC triangle is equilateral, AB = BC = AC = 30 cm.

Answer: The length of the AB side is 30 cm.



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