In a triangle ABC AC = BC. Angle C = 116 degrees. find the outer corner of the CBD.

univerkov | December 2, 2020 | education

Find: ∠СВD
Decision:
AC = BC (by condition), therefore,
∆ABC – isosceles, therefore, ∠А = ∠В = (180-116) / 2 = 64/2 = 32 ° (since the sum of the angles in a triangle is 180 °)
∠CBD = 116 + 32 = 148 ° (by the property of the outer corner of the triangle)
Answer: 148 °.

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