In a triangle ABC AC = BC, the angle C is 50 degrees. find the outer corner of the CBD.

In triangle ABC, sides AC = BC,

Find the outer angle CBD if the angle C is 50 °.

1) The sum of all the angles of the triangle is 180 °, then we find the angle A and angle B.

Since angle A and angle B are equal, then:

Angle A + angle B + angle C = 180 °;

2 * angle B + 50 ° = 180 °;

2 * angle B = 180 ° – 50 °;

2 * angle B = 130 °;

Angle B = 130 ° / 2 = 65 °;

2) Since the inner angle of the triangle is already known, then the outer angle CBD can be found.

Angle CBD = 180 ° – angle B = 180 ° – 65 ° = 100 ° + 80 ° – 65 ° = 100 ° + 15 ° = 115 °;

Answer: angle CBD = 115 °.