In a triangle ABC, AC is equal to BC, the height of CH is 9 AB is equal to 20, find tgа

Since, by condition, AC = BC, the triangle ABC is isosceles.

The height CH of the isosceles triangle ABC is also its median.

Then the triangle ACH is rectangular, AH = BH = AB / 2 = 20/2 = 10 cm.

In a right-angled triangle ACH, tgCAH = CH / AH = 9/10.

Answer: The tangent of the angle BAC is 9/10.



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